Where \(n = 2^k, k \in \mathbb{N},\) $$\displaystyle\sum_{i=2}^{i=n} j x^{i} = {n-1 \over 2}$$ for \(i j = n\)
alternatively \(f(0) = 0\),\(f(n+1) = 2f(n) + x^{{2}^{n+1}} - \frac{1}{2}\)